Given a voltage of 50 microvolts and a sensitivity of 10 microvolts/mm, what is the resulting amplitude?

Given a voltage of 50 microvolts and a sensitivity of 10 microvolts/mm, what is the resulting amplitude?

• A. .2uV/mm
• B. 5mm
• C. 5uV/mm
• D. .2mm

Answer: (B)

To determine the resulting amplitude when given a voltage and a sensitivity, the formula used is: \[ \text{Amplitude} = \frac{\text{Voltage}}{\text{Sensitivity}} \] In this scenario, the voltage is 50 microvolts, and the sensitivity is 10 microvolts per millimeter. By substituting these values into the formula, we get: \[ \text{Amplitude} = \frac{50 \text{ microvolts}}{10 \text{ microvolts/mm}} = 5 \text{ mm} \] This calculation shows that the amplitude of the recorded signal is 5 mm. This means that, in the context of electroencephalography, the visual representation of the electrical brain activity would extend to an amplitude of 5 mm on the tracing. Understanding this relationship between voltage and sensitivity is crucial for interpreting EEG readings accurately, as it affects how the data is visually displayed on the recording equipment.

To determine the resulting amplitude when given a voltage and a sensitivity, the formula used is:

[ \text{Amplitude} = \frac{\text{Voltage}}{\text{Sensitivity}} ]

In this scenario, the voltage is 50 microvolts, and the sensitivity is 10 microvolts per millimeter. By substituting these values into the formula, we get:

[ \text{Amplitude} = \frac{50 \text{ microvolts}}{10 \text{ microvolts/mm}} = 5 \text{ mm} ]

This calculation shows that the amplitude of the recorded signal is 5 mm. This means that, in the context of electroencephalography, the visual representation of the electrical brain activity would extend to an amplitude of 5 mm on the tracing. Understanding this relationship between voltage and sensitivity is crucial for interpreting EEG readings accurately, as it affects how the data is visually displayed on the recording equipment.